-532=-10x^2+15x-12

Solution for -532=-10x^2+15x-12 equation:

-532=-10x^2+15x-12

We move all terms to the left:

-532-(-10x^2+15x-12)=0

We get rid of parentheses

10x^2-15x+12-532=0

We add all the numbers together, and all the variables

10x^2-15x-520=0

a = 10; b = -15; c = -520;
Δ = b2-4ac
Δ = -152-4·10·(-520)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-145}{2*10}=\frac{-130}{20}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+145}{2*10}=\frac{160}{20}
=8
$